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[Post New]16 Mar 2008 23:10:05 IST
    Subject: Re:integrals
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kasirajan.1990 (1084)

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Olaaa!! Perrrfect answer. 204  [236 rates]
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divide num n denom by cos^4x we get [ 0][ pi/2] { 2tanx sec^2x } / { tan^4x + 1 }

                                                       = [ 0][ pi/2]tan^(-1) (tan^2x) = pi/2
kasirajan



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