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BALGANESH (672)

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Olaaa!! Perrrfect answer. 104  [180 rates]

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v0  =  initial vel of sphere
v1  = vel of sphere after colln
v2  =  vel of block after colln
 
from fbd
 
 
 
2Jcos = mv1 -  (-mv0)
therefore
J = m(v1 + v0 ) .....................1
 
Jsin = mv2 ..........2
 
subst 1 in 2  we get
 
2mv2 / root 3 = mv1  + mv0 .....................3
 
now e = - v2sin - v1cos / -v0cos
on solving  ev0 - root3v2 = v1 ...................4
 
subst 4 in 3  and solving we get
 
v2 = v0m( 1 + e )root3/2M + 3m
 
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