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Discussion Response Post to:
NCERT Question
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17 Mar 2008 15:29:08 IST
Subject:
Re:NCERT Question
layman
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The equation of the plane is:
x/a+y/b+z/c =1
so distance from (0,0,0) is:
p=1/root(1/a^2 + 1/b^2 +1/c^2)
and so rearranging you get the answer.
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