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ramkumar_november (1270)

Blazing goIITian

Olaaa!! Perrrfect answer. 230  [290 rates]

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total posts: 407    
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Here is mine......
 
sin(A+B+C);=;cosAcosBcosC(tanA+tanB+tanC-tanAtanBtanC)
 
cos(A+B+C);=;cosAcosBcosC(1-tanAtanB-tanBtanC-tanCtanA)
 
tan(A+B+C);=;
 
tan(n	heta);=;rac{nC_1tan	heta-nC_3tan^3	heta+nC_5tan^5	heta- ;;...........}{1-nC_2tan^2	heta+nC_4tan^4	heta-;;...........}
 
 
sin(A+B)sin(A-B);=;sin^2A-sin^2B;=;cos^2B-cos^2A
 
cos(A+B)cos(A-B);=;cos^2A-sin^2B;=;cos^2B-sin^2A
 
 
 
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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