same as tht of above guy..but considering "giving solns"..wic is really amazing..
the expression inside tht sumation wen simplified gives.. 2^n + {2^(n+1) - 1}/n+1..now tht is equal to ur 2^8 - 1 / 6..
the rhs misses a factor of 2..by tht i mean 2 is left below it..
similarly lhs shud have have one 2 missing out..
solving lhs..{ n.2^n + 2^n + 2^(n+1) -1..} /n+1... ur numerator has zero exponent of 2..(it is obviously odd).. so n+1 is having 2's exponent as 1.. so next task is to find tht n.. numerator in rhs is 21.. so (n+2)(2^n +1) = 24 (as n+1 is even).. n+2 is definitely odd.. 2^n +1 is odd ! so no soln..
Moderation Team
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