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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 21:03:16 IST
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hmm.suppose that the integral is equal to
A/x+1 + b/x+2 + c/x+3.......
then take lcm... so u get
1 = (x+3)*(x+2)A + (x+1)(x+3) + (x+1)(x+2)C..
now put x= -1.. so u get 1= (A)(2)(1).. in this way .. by putting x=-2 and x=-3.. u get the values of b nd c resp...
then put them in the integral and proceed.
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