i have another way to solve that continuity ques.......
main problem comes when solving the R H L........
= h0 ( (h +bh2) - h) / bh3/2
taking h common we get...
= h0 ( (1 +bh) - 1) / bh
now substitute 1+bh = em.....for real m..... now as h --> 0 then em-->1 so m -->0.......changing the limits now....we have
=m0 ( em/2 - 1 ) / ( em - 1 )
now multiply and divide by m/2.....
= 1/2 is the final result........
............................................................................................................................................................................................
There's Light at the end of every Tunnel, so KEEP MOVING....
Best of luck to all my mates....
............................................................................................................................................................................................
Moderation Team
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(h +bh2) - 
0 ( 
