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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 19:47:17 IST
Accepted Answer [?]
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IN the frame of lift , the downward force on the body is m(g+a)
Relative displacement is 0.
So 0 = ut - 1/2(g+a)t^2
(g+a)t/2 = u
2u/t - g =a
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this reply: 15 points
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in 3 votes ) [?]
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