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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 22:11:36 IST
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K man.. here it goes:
For adiabatic expansion: PV^gamma = C
Taking logs we get lnP + gammalnV = lnC
which gives dp/P + gamma dv/V = 0
dp = -gammadvP/V
NOw since frequency is small we can assume P = Po + mg/A and V = Vo
maA = - gamma Adx (Po + mg/A)/Vo
Now we can find omega.
PS: Didnt see HC Verma :) but dont rate if u dont like whatsoever.
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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