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 Discussion Response Post to:
Nice
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Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:35:00 IST
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u can write the given expression as
(3^m + 2^m)*(3^m + 4^m)
m = 5k given in qn..
(3^5k + 2^5k )*(3^5k + 4^5k )
for k =1
we get 275*1267/1991 = 175
since it is true for k= 1
by induction we can say that it is true for all k in N
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this reply: 17 points
(with 3 
in 4 votes ) [?]
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