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pardesi (570)

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Olaaa!! Perrrfect answer. 106  [126 rates]

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f(0)=2,,,,say the function has a period T then
f(T)=2
so at that poit T both Cos T=1 and Cos (sqrt{2}T)=1
the first gives T=2mpi for some integre m
and the second gives sqrt{2}T=2npi for soe integer n
which is a contradiction unless both m=n=0 ...so the function can't be periodic


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