let a1 be the accln of the m relative a , down the incline , therefore its horizantal componenet is a1cos
,therefore its original accln in the horizantal directn =a1cos60 - a now let N be the normal reaction of m on M therefore we get the eqn
Nsin = Ma = m(a1cos60 - a)
sust the value we get 2(m+M)a/m
sorry unable to attach diagram
Moderation Team
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