my ans is f(x)=f'(0)*x + x^2/2 method...its not std but here goes the imp point is tht the 2 variables a and b are independent of each other...i.e with respect to 1 the other is a constant
so d(a)/db=0 diff the given eqn wrt b v get: f'(a+b)=f'(b)+a now put b=0 v get f'(a)=f'(0) + a integrate f(a)=a*f'(0) + (a^2)/2 + c(c=0 easy to show) f(a)=a*f'(0) + (a^2)/2 the function cud be known exactly if f'(0) is known but i dun think it is
Moderation Team
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