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[Post New]1 Mar 2007 18:37:38 IST
    Subject: Re:difrential equ
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KAB (1674)

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y=Aex+B
dy/dx=Aex
So A=(dy/dx)/ex
d2y/dx2=Aex
d2y/dx2=dy/dx
So the required diffrential equation is d2y/dx2-dy/dx=0
ADARSH
NITK Surathkal

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