he answers 34 qns as a, 36 as b, 18 as c, 12 as d now, if the right answer to a qn is a, there is 0.34 probability that he answers it correctly for all 34 qns answered correctly, he has to do it 34 times, ie (0.340(0.34)...34 times ie (0.34)^34 similarly for all options and multiplying , we have
P=(0.34)34(0.36)36(0.18)18(.12)12
it is in the order of 10 raise to -57
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