sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: newton's law of cooling
Forum Index -> Thermal Physics -> View Full Question like the article? email it to a friend.  
Author Message
coolvignesh (196)

Hot goIITian

Olaaa!! Perrrfect answer. 26  [59 rates]

coolvignesh's Avatar

total posts: 179    
online Online
hey..
do you remember stefan's law...
that E = AT4
 
newton took that difference b/n the surroundings and body be smalll
let that differnce be T
and temp. of surrounding be T0
 
then, heat radated from the body will be
dQ/dt =  A{( T0 + T)- T0  raised to the power 4}     
         = AT0^4 {(1 + T/T0 )4 -1 }
let AT0 ^4 = k as it is a constant
so...
mC(dT/dt) = k* ( 1 + (4T/T) - 1)  after binomial expansion.....
as del T is very small compared to T
-1 and +1 will get cancelled in the brackets...
rearranging ...
we will get dT/dt is directly proportional to del T......
as all other units are constant.... so dT/dt = K T  where K is constant....
it is the exact stament of newtons law of cooling......
if you integrate the above equation....
 you will get you will get temp. T after time 't' will be equal to
T= T0  + { Tinitial  - T0} e-Kt
 

size doesnt matter, brains do...
vignesh
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya