sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: question on wt
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
akhil_o (2709)

Blazing goIITian

Olaaa!! Perrrfect answer. 435  [702 rates]

akhil_o's Avatar

total posts: 1451    
offline Offline
On the equator,
the weight recorded would be minimum
this is due to centrifugal force provided by rotation of earth

F=centrifugal force

F=mw2r
w=2pi/(1 hour)
=2 pi/(3600 sec)
a=w2r=(3*10-6)6400000
a=w2r=19.49 m/s2since this is greater than g, the man would be thrown off and feel weightless

" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

 Aakash Institute IIT/ AIEEE/ Medical Crash Course
Name  
E-mail  
Phone  
Mobile  
** Hurry. Exclusive goIIT Offer. Limited Seats Only!
available in: New Delhi, Amritsar, Bhatinda, Bokaro, Chandigarj, Dehradun, Guwhati, Hyderabad, Indore, Jaipur, Kanpur, Karnal, Kolkata, Kota, Lucknow, Ludhiana, Mumbai, Noida, Patiala, Patna, Pune, Ranchi, Varanasi
Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Aakash-IITJEE : AIEEE
Aakash-IITJEE : DCE
Aakash-IITJEE : MHTCET
Aakash Institute : AIPMT
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya