hi friend it was an exelent Q

here it is

 

apply F(a+b-x)dx=F(x)dx  also put x=-h

you will get

1-h²/logh.dh   limit 0-1

now take e^y=h you will get

 

_{[-infinite ]}^{[0 ]} e^y/y.dy   -_{[-infinite ]}^{[0 ]}e^2y/y.dy--------- multiply this with 2 and divide also

and take 2y=z in second part

 

you will get the value =0

bye

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