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[Post New]22 Mar 2008 19:42:28 IST
    Subject: Re:progression rates aasured
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raulrag009 (1217)

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Q4\\\\ The\;series\;formed\;is\\\\ 1,1+3,1+3+5...........n\;terms\\\\ General\;term\;t_{n}=1+3+5+7+9+...........(2n-1)\\\\ t_{n}=2n^{2}-n\\\\ Sum\;it\\\\ S_{n}=\frac{2n(n+1)(2n+1)}{6}+\frac{n(n+1)}{2}\\\\ S_{n}=\frac{n(n+1)(4n-1)}{6}
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