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Discussion Response Post to: Heat transfer (HCV)

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23 Mar 2008 01:26:05 IST

Subject: Re:Heat transfer (HCV)

BALGANESH (682)

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106 [182 rates]

total posts: 309
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x = l

H = -KAdT/dx

A= @r^2 ( @ = pie )

from the figure

r2/x2 = r1/x1 = r/x = C ( therefore r =Cx) ........1

H = - K (r@)^2 dT/dx

dT = -[ H /@KC^2 ] dx/x^2

integrating T from T2 to T1

and x from x1 to x2

we get

T2 - T1 = H/@C^2 [ 1/x1 - 1/x2 ] .........2

but x2 - x1 = -l

and from 1 x1 x2 = r1r2/C^2

ON SUBST in 2we get

H = (T2 -T1 )Kr1r2@/l

this reply: 20 points (with 4 Olaaa!! Perrrfect answer.

in 4 votes ) [?]

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