by amangupta
25. at highest point the normal acc. is g, it can be considered a circle with centirpetal acc=g
thus v^2/r=g
or r=V^2/g and v at highest point is gcosx.
thus answer is (vcos theta)^2/g.
and 27(c) the normal reaction is mv^2/r
and frictional force is the only force acting in tangentail direction thus acc=uN/m
=uv^2/r and since it is opposing motion, the negative sign is added
Moderation Team
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