IIT JEE , AIEEE Forum - Physics , Mechanics - H C Verma

BALGANESH

So we have the inst. acc. as -v²/r
And we all know chain rule !!
So we can write V=dS/dt=dS/dV*dV/dt ---------------------------(1)

by madmax , refer earlier post

Rearranging we get the eqn they have given which is dv/dt=v(dV/dS)

I'll just continue with eqn (1)
Take dv on the other side ,substitute dV/dt=v²/r and rearrange the eqn to get

(1/V)dV=(-/r)dS

The question is for one revolution so integrate S from 0 to 2r and dV from Vo to V........where Vo is init vel

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