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[Post New]23 Mar 2008 11:54:27 IST
    Subject: Re:evaluate this integral..
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raulrag009 (1217)

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Olaaa!! Perrrfect answer. 205  [301 rates]
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Here\\\\ I=\int_{0}^{\frac{1}{4}}{\frac{dx}{1+\sqrt{\cot{2\pi\;x}}}}\\\\ I=\int_{0}^{\frac{1}{4}}{\frac{\sqrt{\tan{2\pi\;x}}}{1+\sqrt{\tan{2\pi\;x}}}}..............(1)\\\\ Apply\;property\\\\ I=\int_{0}^{\frac{1}{4}}{\frac{dx}{1+\sqrt{\tan{2\pi\;x}}}}.............(2)\\\\ Add\;(1)\;and\;(2)\\\\ 2I=\int_{0}^{\frac{1}{4}}{\frac{\sqrt{\tan{2\pi\;x}}}{1+\sqrt{\tan{2\pi\;x}}}}+\int_{0}^{\frac{1}{4}}{\frac{dx}{1+\sqrt{\tan{2\pi\;x}}}}\\\\ 2I=\int_{0}^{\frac{1}{4}}{dx}\\\\ 2I=\frac{1}{4}\\\\ I=\frac{1}{8}
 this reply: 12 points  (with 2 Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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