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kishan12 (309)

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Olaaa!! Perrrfect answer. 59  [66 rates]

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x1,x2,x3...........x50 are fifty real numbers such that x(r)<x(r+1) [here (r) and (r+1) are in subscript] for r=1,2,3.......49.Five numbers out of these are picked up at random.The probability that the five numbers have x20 as the middle number is..........

Ans:[20C2 * 19C2]/50C5


    
 

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