1>Let molarity of acid be M. So,since millieq. are equal, M*25=17.7*0.185 So,M=0.13098. Now,u know that for weak acid,a=root(Ka/C) where a is degree of dissociation. Ka is given and C is what we have calculated as M. So,a comes out to be 0.021. Now,the conc. of H+ will be C*a. So,Ph=-log[C*a]=2.57
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