There are 10 questions in section A .and each question carries 1 mark ...thus max marks is 10 There are 10 questions in section B and each question carries 3 mark ...thus max marks is 30 Thus total max marks obtainable is 40 ...and there is only way to do so ..that is get all questions right ...P of which is (1/5)^10 * (1/15)^10 ...Thus P of getting mark less than 40 is 1-[(1/5)^10 * (1/15)^10]