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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Mar 2008 23:43:05 IST
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2root3 -root3cosx + 4sin2x = sinx
=> root3 + 2sin2x = sinx/2 + root3cosx/2
=> root3 + 2sin2x = sin(30+x)
=> 2(sin60 + sin2x) = sin (30 +x)
=> 4sin (30+x)cos(30-x) = sin(30+x)
=> sin(30+x)(1 - 4cos(30-x)) =0
=> sin(30+x) =0 OR cos(30-x) = 1/4
After this is easy but hectic to type.
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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