If the radius of the circle at the bottom u have drawn is also l, then d ans is rt. if so, Centre of mass of rod rotates in a circle of radius l/2. Force for this can be provided only by the horizontal component of hinge force. m2l/2 is the centripetal force, n this is equal to horizontal component of hinge force.
I dont think magnitude of angular momentum is ml2/12.
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2l/2 is the centripetal force, n this is equal to horizontal component of hinge force.
l2/12.
