IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

BALGANESH

Total volume after reactn = 83.2

O2 + CO2 = 83.2

but vol of CO2 = 10.8 ...................1

Therefore vol of excess O2 =72.4

therefore O2 reacted =12.6 g.................................2

CH4 + 2O2 = CO2 + 2H2O ( let vol of CH4 = x )

from the reactn vol of O2 reacting with it =2x and vol of CO2 produced =x.......3

now 2H2 + O2 = 2H2O ( let vol of H2O = 2y )

Therefore vol of O2 ractn with it = y..................4

let vol of CO2 present in the mix initially = z............5

from 1,2,3,4,5 we get the eqns

x+ 2y + z =15 ( total vol of mix)

x + z = 10.8 ( total vol of CO2 )

2x + y = 12.6 (total vol of O2 reactin )

solvin the eqns CH4= 5.25g = 35 %

H2 4.2g = 28 %

rest = CO2 = 37 %

hope satisfied this time