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[Post New]24 Mar 2008 06:22:26 IST
    Subject: Re:electrostatics
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konichiwa2x (2342)

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Olaaa!! Perrrfect answer. 440  [511 rates]
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Option "B" is definitely not right. Inside a cavity, the electrical field is 0 due to electrostatic sheid.
 
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Hence O' , 'p' and 'r' are at the same potential. So option 'b' and 'c' are wrong which leaves us only with option 'a'.
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