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iberis22 (575)

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Olaaa!! Perrrfect answer. 105  [130 rates]

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Both LAH and NaBH4 don't reduce olefins(even if present in conjugation). But there is one exception found in reduction of - aryl-, unsaturated compounds. With LAH, the double bond is also reduced along with the carbonyl. But still, NaBH4 doesn't reduce the double bond and reduces only the carbonyl.
 
                                 NaBH4,                              Xs, LAH
  PhCH=CHCH2OH <-----------------  PhCH=CHCHO ------------->PhCH2CH2CH2OH
                                or LAH, -10oC                     ether,350C
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