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[Post New]24 Mar 2008 11:06:54 IST
    Subject: Re:Integrate
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raulrag009 (1205)

Blazing goIITian

Olaaa!! Perrrfect answer. 203  [298 rates]
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Put
 
  \log{x}=t\\\\ x=e^{t}\\\\ dx=e^{t}dt
 
 
Now
 
\int{e^{t}[\frac{(t^{2}+1-2t)}{(1+t^{2})^{2}}]}dt\\\\ \int{e^{t}[\frac{1}{1+t^{2}}-\frac{2t}{(1+t^{2})^{2}}]}dt\\\\
 
Let
 
  f(x)=\frac{1}{1+t^{2}}\\\\ f
 
Integral becomes
 
\int{e^{t}[f(t)+f
 
rest is simple
 this reply: 15 points  (with 3 Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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