IIT JEE , AIEEE Forum - Physics , Mechanics

elastiboysai

Suppose the distances between the drops and the top of the buliding is S1,S2,S3,S4
S1=16 m given,
Suppose T is the time interval after which a drop detaches itself from the roof.
Then clearly,
S1,S2,S3,S4 are covered by the drops D1,D2,D3,D4 in time interval 4T,3T,2T,T
drops fall wid zero initial velocity, S=gt^2/2

so for drop D1,
t=4T,S=S1=16 m
T^2=1/4.9

for drop D2,
t=3T, S=S2
S2=4.9*3T^2 plug in for T
S2=9m
imiliarly for drop D3,
t=2T
S3=4.9*2T^2=4m

for drop D4
S4=4.9*T^2
S4=1m

so dist between the drops
D1 D2 --7m
D2 D3--5m
D3 D4--3m
D4 D5 --1m

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