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Qn 2)

Number of moles of H⁺ = 10^-10

Number of moles of OH^- = 2 x 10^-5

Now, as the number of H⁺ ions is less, it will completely react with the available OH^- ions to form water, and the resulting Hydroxide ions contribute to the pOH.

Hence, number of moles of OH^- remaining = 1.99 x 10^-5

Hence, pOH = 4.6989

Hence, pH = 14-pOH = 9.301

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