IIT JEE , AIEEE Forum - Physics , Mechanics - i have so many doubts in friction,hc verma........

waterdemon

Q.33)

The Hanging mass is "M" and hence the pulling force is "Mg"

The mass in motion is (m+M+M')

Therefore the acceleration will be:

F= M"a

Where M" = Total Mass

F = (m+M+M')a

Mg = (m+M+M')a

a = Mg/(m+M+M')

The mass "m" will not slide over M' if :

aCos@ = gSin@

Therefore,

MgCos@/(m+M+M') = gSin@

From solving above we get :

M = (m+M')/(Cot@-1)

Hope you find it useful.

Cheers!!!!!!!!!@@@!!!!!!!!!!!

Ask & Discuss Questions with Community & Experts