sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: Gravitation
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
anchitsaini (4352)

Blazing goIITian

Olaaa!! Perrrfect answer. 796  [982 rates]

anchitsaini's Avatar

total posts: 1242    
offline Offline
v1 = velocity of m1
v2 = velocity of m2

conserving momentum--

m1 v1 = m2 v2              -----------1

conserving energy --

m1 v1 2 / 2    +  m2 v2 2 / 2 = Gm1 m2 / r     ---------2

putting value of v2 from 1 in 2 we get --

v1 2 ( m1 + m2) / m2 = 2G m2 / r

v1 = m2  [ 2G / (m1 + m2) r ]

similarly putting value of v1 from 1 in 2 we get --

v2 = m1 [ 2G / (m1 + m2) r ]

relative velocity = v1 + v2 since they are in opposite directions
v r = [ 2G / (m1 + m2) r ] * (m1 + m2)
  
    = [ 2G (m1 + m2) / r ]

Impossible To be Impossible is Impossible
 this reply: 12 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya