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uday_zingtudor (931)

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Olaaa!! Perrrfect answer. 155  [233 rates]

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f(2) = 2 [ 1][1] f(1)  = 2f(1)

f(3) = 2 [1 ][2 ] f(2) = 2[ f(1) + f(2)] = 2[3f(1)] = 6 f(1)


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