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akhil_o (2709)

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Olaaa!! Perrrfect answer. 435  [702 rates]

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Nice question...i am not sure if this is right

let us assume the needle falls at an angle @ with the parallel lines

so the band or area it can be said to cover along 1 line=
2l|sin@|
now
for no intersection,
this band should lie within the lines
so P=2l|sin@|/2a
=l|sin@|/a

now @ moves from 0 to 2 pi continuously
so P=integral of(lsin@/a) from 0 to 2 pi
note the mod sign

so P=4l/a
edit

divide by the sample space(which is from 0 to 2 pi)
P=4l/a*1/2 pi
=2l/a pi


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