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Discussion Response Post to:
how to solve?
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Trignometry
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Author
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25 Mar 2008 00:35:21 IST
Subject:
Re:how to solve?
elastiboysai
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Blazing goIITian
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Nice line of thinking, Sushmi
but deede's approach is also a gud 1.
5^x+1/5^x>=2
By Am Gm inequality,
e^x is real valued for real x,
so -1<sin(e^x)<1
so both can never equal each other
heres a graph
edit: small mistake in d graph , rectified now
this reply: 5
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