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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Mar 2007 21:17:49 IST
Accepted Answer [?]
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Consider the sheet to be lying in yz plane and current is flowing along +z axis. The net field in the neighourhood of sheet will be have field because of sheet Bs and field because of other factors Bo. On one side of sheet field will be Bo+Bs and on other it will be Bo-Bs (Direction of Bs will be opposite on both sides)
Putting Bo+Bs = B1
and Bo-Bs= B2
Bo=(B1+B2)/2 (Here additions are vector additions)
Bs = mu*J/2 (where J is currect density)=(B1-B2)/2
Now consider a unit thin sheet of length l and width w.
It carries a current Jw and hence force on that piece is
F=iBl=JBo*lw
so pressure is JBo=(1/2mu)*(B1-B2)*(B+B2)
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
this reply: 2 points
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