IIT JEE , AIEEE Forum - Physics , Mechanics - i have so many doubts in friction,hc verma........

waterdemon

It is this that see

The friction force that exists between the two blocks is
f₃₇ = (0.3)(10)(3) = 9N

And since the force is being applied on top 2kg block so
the force of 10N will drive only 2kg block whereas the
friction between 2kg and 3kg block will drive 3kg block

So,
Which is equal to
f = 2(0.2)(10) = 4N

And since the force that is driving 3kg block is 4N and
as the friction force is equal to 9N Hence,

The condition of slipping won't be satisfied as for that
the applied force has to be more that limiting friction
which over here is greater.

So the force of 4N will drive both the blocks together,

Hope you find it useful.
Cheers !!!!!! @@@ !!!!!!!!

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