IIT JEE , AIEEE Forum - Mathematics , Algebra

Sushmi

Can't we proceed using binomial theorem for the later part

(1 - x) ^ n = C0 - C1x + C2 x^2 - C3 x^3 ......+(-1)^n x^n

so we can write it like,

1 - (1-x)^n / x = C1 - C2 x^2 + C3 x^3 - ...+( -1)Cn x^n-1

or _[0]

^[1] 1 - (1- x)^n / 1 - (1-x) = [ C1x + C2 x^2/2 - C3 x^3/3 ......+(-1)^n x^n/n ]

wont this give the required value for the later part?

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