sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: FIND THE IMPULSE ON THE PARTILE?
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
karthik2007 (3733)

Blazing goIITian

Olaaa!! Perrrfect answer. 655  [884 rates]

karthik2007's Avatar

total posts: 2806    
offline Offline
Consider one of the sides as the x axis.

Velocity along this line = vi

Now, velocity along the next side, which makes an angle of ( - /n) with the positive x axis is v(-cos(pi/n) + v(sin(pi/n))

required impulse = mass x difference between the two velocity vectors. To get magnitude, take sum of square root fo components

Will nip in at times to solve problems :)
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

 Aakash Institute IIT/ AIEEE/ Medical Crash Course
Name  
E-mail  
Phone  
Mobile  
** Hurry. Exclusive goIIT Offer. Limited Seats Only!
available in: New Delhi, Amritsar, Bhatinda, Bokaro, Chandigarj, Dehradun, Guwhati, Hyderabad, Indore, Jaipur, Kanpur, Karnal, Kolkata, Kota, Lucknow, Ludhiana, Mumbai, Noida, Patiala, Patna, Pune, Ranchi, Varanasi
Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Aakash-IITJEE : AIEEE
Aakash-IITJEE : DCE
Aakash-IITJEE : MHTCET
Aakash Institute : AIPMT
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya