sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: BALLOON RISES....
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
hash_include (381)

Scorching goIITian

Olaaa!! Perrrfect answer. 59  [102 rates]

hash_include's Avatar

total posts: 203    
offline Offline
distance travelled by balloon in first 5 sec = 1/2 * 3 * 25 = 75/2

vel of balloon after 5 sec = 3*5 = 15

let the balloon and stone meet (t + 5) sec after the balloon starts going up

h = ht at which they meet =  1/2gt^2

also, h1 = distance traveled by balloon from T=5sec till T=t+5
h1 = 15*t + 1/2*3*t^2

h - h1 =  75/2
solve for t and get hence get u from 0 = u - gt
 

JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php

join the revolution!!
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya