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[Post New]25 Mar 2008 18:06:52 IST
    Subject: Re:Centre of mass & conservation of lenear momentum
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elastiboysai (2327)

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Olaaa!! Perrrfect answer. 421  [532 rates]
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2/3
See the figure
obv. the triangle is equilateral
so=30
now
by conservation of momentum
mu=2mvcos30
v=u/ 3
e=vel seper/v approach along common normal
=v/ucos30
(u/ 3)/u3/2
=2/3

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