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 Discussion Response Post to:
LOG
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2008 19:47:51 IST
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Now that u hv changed it..
[0 ] [infinity ] log(x^2+1)/x *1/x^2+1 dx
now substitute x=tan a
[0 ] [pi/2 ]log(sec^2a/tana)da
[0 ][pi/2 ]log(1/sina)+log(1/cosa) da
shud be pi *log2
using the fact that
[0 ][pi/2 ]logsina da= -pi/2 *log2
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this reply: 5 points
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Moderation Team
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