The position vector of a particle of mass 1kg moving in space is given by r=(2 2t2 i+3 3t3 j+(1/ 2)t4 j)m. Then the value of mod( 01 r x (d2r/dt2).dt) is [t is in second]. One method is finding d2r/dt2 and calculating cross product but that is obviously too tedious.There has to be a better method,maybe since d2r/dt2 is accelaration. But i cant go further.Can anyone plz try??
MaNuTd RoXxXx..MaNuTd 2 WiN PrEmIeR LeAgUe ThIs SeAsOn ToO AlOnG WiTh ChAmPiOnS LeAgUe.....HaiL RoNaLdO ...HaiL LaMpArD...
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2t2 i+3
1 r x (d2r/dt2).dt) is [t is in second].
