|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2008 21:18:50 IST
|
|
|
ans A) 10 A at its peak
we get R = 10 ohms..
C = 1/ pi * 10^(-3)
=> wC = 2* pi * 50 * 1/ pi * 10 ^(-3)
= 0.1
so, X = reactance = 10 ohms
=> Z = root(10^2 + 10^2) = 10 rt2
so, Irms = 100/10rt2 = 5 rt 2
=> Ipeak = rt 2 * 5 rt 2
= 10 A
|
JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
join the revolution!! |
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
