Well for  finding his car , total number of ways = ^N-1C_R-1 ?.(as 1 car is his own , we wont count it)

Where N = 25 (total number of cars standing)

R = no. of places still occupied = 15

So total no. of cases = ²⁴C₁₄

As neighbouring slots are empty , the 14 cars (excluding his car) must be parked in 21 places?..

Number of favourable cases = ²¹C₁₄

So probability = ²¹C₁₄/²⁴C₁₄ = 15/253

dats my method dude