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[Post New]26 Mar 2008 19:43:50 IST
    Subject: Re:conceptual doubt emergency
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hash_include (381)

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Olaaa!! Perrrfect answer. 59  [102 rates]
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see the diagram..

velocity of the string = u = dx/dt
velocity of block = v = dy/dt.

applying pythyagoras theorem, we get

x^2 = L^2 + y^2

differentiate wrt 't'

2x dx/dt = 0 + 2y dy/dt
solving we get..
v = dy/dt = u (x/y)

but x/y = sec according to figure..

so v = u sec


EDIT: enlarge the diagram to see it clearer.

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